What is the HCF of {{curQ.nums.join(', ')}}?
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You found the common factors {{comFacs.join(', ')}}
Notice that {{comFacs.join(' x ')}} = {{prodOfCFs}}
After dividing by {{comFacs.join(' and then ')}}
the numbers in the question become {{curQ.nums.map(n => n/prodOfCFs).join(', ')}}
Is there a number that divides all of those?
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Think of a number that divides all three of {{curQ.nums.join(', ')}}.
You have found enough useful common factors.
Can you use what you found to get the answer to the original question?